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Nicholas Gaerlan
9,501 PointsMy answer seems correct
I tested block by rewriting it as a script that takes an input of either a string or number and then instead of return I just used print to see if it generates the expected outcome. Here's the code I used outside of the test:
def squared(num):
try:
print(int(num) ** 2)
except ValueError:
print(len(num) ** 2)
squared(num = input("square what? "))
That's not the answer I gave for the test of course. I just used it to see if my definition of the "squared" function would generate the expected result.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
try:
return (int(num) ** 2)
except ValueError:
return (len(num) ** 2)
1 Answer
Steven Parker
231,275 PointsYou're halfway there.
If the argument is or converts to a number, you're good. But when an exception is thrown you don't want to output the square of the length, but instead the instructions asked you to "return the argument multiplied by its length".
Nicholas Gaerlan
9,501 PointsNicholas Gaerlan
9,501 Pointsthat must've been it. I simply had the length value "squared" as my exception result. I rewrote it to account for all the scenarios correctly. however, even though I found 2 different ways to do it, the answer wouldn't accept it. I just kept giving different ways to accomplish it until one of them finally worked.