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Start your free trialManuel Gutierrez
1,028 Pointsmultiply
have to multiply integerOne with floatOne
<?php
//Place your code below this comment
$integerOne =1;
$integerOne = $integerOne + 5;
var_dump($integerOne);
$integerTwo =2 ;
$integerTwo = $integerTwo -1;
var_dump($integerTwo);
$floatOne = 1.5;
$integerOne= $intergerOne * $floatOne;
echo"$integerOne";
?>
1 Answer
KRIS NIKOLAISEN
54,971 PointsOne error message received is to not change the value of $integerOne when displaying the product. You can use echo without the intermediate step.
echo $integerOne * $floatOne;
Note I also corrected a typo with $integerOne instead of $intergerOne
Then just remove the var_dump statements and you should pass.