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Start your free trialShouvik Lahiri
745 PointsMultiplication Exercise
Create a New Float Variable named $floatOne with a value of 1.5. Without changing the value of $integerOne or $floatOne, multiply $integerOne by $floatOne and display the results.
In this case, the result will be either 1.5 or 9
both results are showing wrong. Whats the thing i am missing out
<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$integerOne = $integerOne + 5;
$integerTwo = $integerTwo - 1;
$floatOne = 1.5;
var_dump ($integerOne * $floatOne) ;
?>
2 Answers
Daniel Gauthier
15,000 PointsHey Shouvik,
You're really close, but you're trying to use var_dump when you need to be using echo.
The following code will pass:
<?php
$integerOne = 1;
$integerTwo = 2;
$integerOne += 5;
$integerTwo -= 1;
$floatOne = 1.5;
echo $integerOne * $floatOne;
?>
You almost had it, great work :D
Good luck with the course!
Jack O'Brien
986 Points<?php
$integerOne = 1; $integerTwo = 2;
$integerOne += 5; $integerTwo -= 1;
$floatOne = 1.5; echo $integerOne * $floatOne;
?>
Hazem mosaad
15,384 PointsHazem mosaad
15,384 PointsHi I don't understand you the result float(9) correct what is the problem?