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Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Andrew Wilcox
Andrew Wilcox
4,374 Points
Posted by Andrew Wilcox
Andrew Wilcox
4,374 Points

minutes.py (stuck by one second???)

I don't understand, says, got the wrong number (the number I need ends on seven and my output ends on 6) I am off just by one unit. just curious what's happening.

Thanks in advanced !

minutes.py 
import datetime

def minutes(t1, t2):
    duration = t1 - t2
    seconds = duration.total_seconds()
    minutes = int(seconds / 60)

    return minutes
pierreilyamukuru
pierreilyamukuru
9,831 Points

Here are two things I can suggest you: 1) Import math and round up with ceil function 2) Remove integers ( int) when using math Ceil Your function looks great and only using ( math.ceil)

2 Answers

Alex Koumparos
seal-mask
.a{fill-rule:evenodd;}techdegree
Alex Koumparos
Python Development Techdegree Student 36,887 Points
Alex Koumparos
.a{fill-rule:evenodd;}techdegree
Alex Koumparos
Python Development Techdegree Student 36,887 Points

Hi Andrew,

I copied and pasted your code and got the following error:

Bummer! Got the wrong number of minutes. Expected 1507, got -1506.

So the error in your case is not one unit, it is 3013 units (-1506 vs +1507).

3012 of the units are due to you putting your variables in the wrong order in your subtraction (i.e., 2 - 3 is not the same as 3 - 2).

As for the remaining one unit, this is because you are getting a whole number by type casting from float to int. This conversion always truncates (rounds down). But the question is asking you to round, which rounds to nearest (which in this case would be rounding up). Hence your difference of 1. There is a specific function for rounding.

Hope that clears everything up for you.

Cheers

Alex