Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Deborah Watson
2,614 PointsMake sure you're creating all 4 columns: id, first_name, last_name, and favorite_rock_id.
Now recreate the MEMBERS table with the new FAVORITE_ROCK_ID column, and make sure it has a foreign key constraint to the ID column of the ROCKS table. The columns should now be: ID, FIRST_NAME, LAST_NAME, and FAVORITE_ROCK_ID.
CREATE TABLE MEMBERS ( ID INT PRIMARY KEY, FIST_NAME VARCHAR(255), LAST_NAME VARCHAR(255), FAVORITE_ROCK_ID REFERENCES ROCKS(ID) );
Why doesn't this work?
2 Answers
Steven Parker
231,268 PointsWell, you have "FIST_NAME" instead of "FIRST_NAME". But I wasn't able to get it to work even after fixing it.
So there may also be some issue with the challenge itself, I know there was a problem just a few days ago with a different question. You might try writing directly to the Support folks.
I'll also tag Craig Dennis since I believe he fixed the other issue.
Deborah Watson
2,614 PointsIt's working now! Thanks Steven.
Deborah Watson
2,614 PointsDeborah Watson
2,614 PointsThe support folks tell me to post it out here. So frustrating!
Steven Parker
231,268 PointsSteven Parker
231,268 PointsOdd, maybe they ran a "test answer" through that still passes. But hopefully Craig will take a look soon.