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omar talaat
Courses Plus Student 171 Pointslists
'ACTIVE', ['red', 'green', 'blue'], 'CANCELLED', 'FINISHED', 5, ] states.remove(['ACTIVE' ,'CANCELLED' ,'FINISHED' ,5]) he is asking to remove the last item
states = [
'ACTIVE',
['red', 'green', 'blue'],
'CANCELLED',
'FINISHED',
5,
]
states.remove(['ACTIVE' ,'CANCELLED' ,'FINISHED' ,5])
2 Answers
Ken Alger
Treehouse TeacherOmar;
If we look at the provided list and how the remove() method works we need to pass in an item to the remove() method for it to remove. remove() removes the first matching value it finds, unlike del() or pop() which removes things based on an index.
For example, if we have a list:
colors = ["red", "green", "blue"]
And want to remove green from the list, we can utilize remove("green") to remove that item.
colors.remove("green")
results in colors being the new list ["red", "blue"].
With all of that in mind, try the challenge again passing into remove() just the item the challenge is wanting to be removed from the provided list.
Post back if you are still stuck.
Happy coding! Ken
Ken Alger
Treehouse TeacherIt doesn't require an index, true, but internally it is removing the last index by default. But passing in pop(1) would, in the colors example above, also remove "green" from the list.
Ken
Aeyzechiah Vasquez
2,070 PointsI see, thank you!
I also see now that pop() isn't just some legacy method; pop(n) is more powerful and can remove (and return) an element from anywhere in the list, rather than only from the end. I'm still getting used to "Pythonic" thinking and these small insights are very helpful!
Aeyzechiah Vasquez
2,070 PointsAeyzechiah Vasquez
2,070 PointsHi learners!
I would like to add that [List].pop() does not require an index. The pop() method automatically removes the last item of your list. It is usually used in the context of Stacks which are designed specially for retrieving the last element.
Keep on! ^^ AZ