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Edwin Chau
Courses Plus Student 5,702 PointsJavaScript code challenge
Complete the assignment to the userName variable by adding a # symbol followed by an all uppercase version of the lastName variable. In other words, using string concatenation so that the final value of userName is "23188XTR#SMITH".
I don't know what I did wrong?
var id = "23188xtr";
var lastName = "Smith";
var userName = id.toUpperCase() + "#" + lastname.toUpperCase();
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>
3 Answers
Rich Donnellan
Treehouse Moderator 27,696 PointsEdwin,
Check your variable names in all code — they are case sensitive!
-Rich
TJ Egan
14,420 PointsShould be:
var id = "23188xtr";
var lastName = "Smith";
var userName = id.toUpperCase() + "#" + lastName.toUpperCase();
You had last*name.toUpperCase(), should have been lastN*ame.toUpperCase
Rich Donnellan
Treehouse Moderator 27,696 PointsSure!
variableName is not the same as variablename.
Got it?
Edwin Chau
Courses Plus Student 5,702 PointsEdwin Chau
Courses Plus Student 5,702 PointsMay I know what you mean by case sensitive?
Sam Baines
4,315 PointsSam Baines
4,315 PointsRich means that the variable names must match completely including where they use upper case and lower case letters. Case sensitive means variable 'ID' is not equal to 'id' because one is in lower case and one in upper case.