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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by ryan backert
ryan backert
75 Points

its to difficult

43t45

Name.java 
// I have setup a java.io.Console object for you named ="ryan can code in java";
String firstName ="%s";
console.printf ("%s code in java /n,firstName);

1 Answer

daniel104729
daniel104729
7,176 Points
daniel104729
daniel104729
7,176 Points

You may want to change firstName to a name like Zoe or Ryan. The issue I am guessing is that you forgot a double quote " after /n and before ,firstName. Also, you probably want \n and not /n. \n is newline and /n is nothing special

You may be discouraging help by saying you think the problem is too difficult

Ole Vølund Skov Mortensen
Ole Vølund Skov Mortensen
27,842 Points

I'll merely add: Remember; it should be referenced to the instance started. if it's within the same class(like yours) it's "this.firstName" other than that, the above is a bare minimum. ' " ' is missing and \n. all great advise!