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Start your free trialChandana Venkatadri
1,763 Points'intAsString' should hold the String representation of the value in 'randomNumber'.
I'm Stuck here help me!
String intAsString = " ";
Random randomGenerator = new Random();
int randomNumber = randomGenerator.nextInt(10);
intAsString = randomNumber + " ";
2 Answers
Grigorij Schleifer
10,365 PointsHi Chandana,
here is my approach:
Random randomGenerator = new Random();
int randomNumber = randomGenerator.nextInt(10);
String intAsString = randomNumber + "";
What error do you get?
Try to write the string declaration and assignment of the integer from the random generator in one line.
Let us know if you find another trick or use my approch.
Grigorij
Chandana Venkatadri
1,763 PointsHI Grigorij,
I think I figured out where I went wrong!
Chandana Venkatadri
1,763 PointsChandana Venkatadri
1,763 PointsThank you :)