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4,228 PointsImagine you have 10 <div> tags on a web page. Each div is 190 pixels wide. Using the two variables in this script, creat
I have tried a lot of different answer I am 90% sure the last one is correct, it is still saying bummer
var width = '190px';
var numOfDivs = 10;
//var width = '190px'; var numOfDivs = 10;
//var totalWidth = 'parseInt(width)' * 'numOfDivs';
var totalWidth = 'parseInt(width)' * 'parseInt(numOfDivs)';
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>
2 Answers
Huzaifa Sajjad Malik
Courses Plus Student 10,823 Pointsvar width = '190px';
var numOfDivs = 10;
//var width = '190px'; var numOfDivs = 10;
//var totalWidth = 'parseInt(width)' * 'numOfDivs';
var totalWidth = 'parseInt(width)' * 'parseInt(numOfDivs)';//here you are treating both the var as strings you have wrapped them in strings.
Solution:
var totalWidth=parseInt(width) * numOfDiv;
//You Parse strings only so that they are converted to the relevant data-type
Huzaifa Sajjad Malik
Courses Plus Student 10,823 PointsBro why are you wrapping the parseInt(width) and numOfDivs in string quotes ' ' just type them without quotes like this just copy and paste this code in the code challenge :) Peace.
var width = '190px';
var numOfDivs = 10;
var totalWidth=parseInt(width)*numOfDivs;
Peter B. Sims
Courses Plus Student 2,896 PointsThanks for keeping it simple, Huzaifa Sajjad Malik. Peace
mohammed mayat
4,228 Pointsmohammed mayat
4,228 Pointsthanks for the quick reponse, still not working
var width = '190px'; var numOfDivs = 10;
var totalWidth = 'parseInt(width)' * 'numOfDivs';