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Start your free trialryan andrew
5,450 Pointsif loop in code not printing?
var message = "";
var search;
var report;
var students = [
{name: 'ryan', age: 29, location: 'toronto'},
{name: 'deku', age: 21, location: 'japan'},
{name: 'jack', age: 31, location: 'vaughn'},
{name: 'erwin', age: 29, location: 'markham'}
];
function print(message){
var outputDiv = document.getElementById('output');
outputDiv.innerHTML = message;
}
function getStudentList(students){
var report = '<h2> Name: ' + student.name + '</h2>';
report += '<p> Age: ' + student.age + '</p>';
report += '<p> Location: ' + student.location + '</p>';
return report;
}
while (true){
search = prompt('Please enter a students name [ryan] or [quit] to exit program');
if ( search === null || search.toLowerCase() === 'quit') {
var message = '<p> See you next time! </p>';
print(message);
break;
}
for (var i = 0; i < students.length; i += 1){
var student = students[i];
if (student.name === search) {
var message = getStudentList();
print(message);
}
}
}
2 Answers
Steven Parker
231,275 PointsI see three issues:
The "getStudentList"" function takes an argument named "students" (plural), but in the body of the function there are references to "student" (singular) which has not been defined.
Also, when function is called, no argument is passed to it.
Finally, each call to the "print" function replaces any and all text printed before. Try making it add to the output instead of replacing it:
outputDiv.innerHTML += message; // note: += instead of =
Vasanth Baskaran
4,333 PointsHi Ryan
The getStudentList( students ) function is expecting an parmeter, but in your code you haven't passed any arguments. Please try once by passing an argument in it.
In our case it is trying to call a function without parameter which doesn't exist.
Thanks
Steven Parker
231,275 PointsSteven Parker
231,275 PointsWhen posting code, use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. Â Or watch this video on code formatting.