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Trenton Spears
Python Development Techdegree Graduate 16,969 PointsI think I'm stuck again... SQLAlchemy Basics Challenge Task 2 of 2 Querying the Movie Database
Today, the theater is updating the list of movies on the sign outside. Create a variable named all_movies. It should hold all of the movies in the database in alphabetical order.
from sqlalchemy import create_engine, Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker
engine = create_engine(‘sqlite:///movies.db’, echo=False)
Session = sessionmaker(bind=engine)
session = Session()
Base = declarative_base()
class Movie(Base):
__tablename__ = ‘movies’
id = Column(Integer, primary_key=True)
movie_title = Column(String)
genre = Column(String)
romance_movies = session.query(Movie).filter_by(genre='Romance').first()
for all_movies in session.query(Movie.all_movies).order_by(Movie.all_movies):
print(all_movies.movie_title)
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsHey Trenton Spears, you are almost there.
Task 2 asks to create the variable all_movies only, no loop or printing required
- the query is based on
Movieas inquery(Movie) - the order_by needs the correct attribute reference, as in
order_by(Movie.movie_title) - need to include
.all()
Post back if you need more help. Good luck!!!
Trenton Spears
Python Development Techdegree Graduate 16,969 PointsTrenton Spears
Python Development Techdegree Graduate 16,969 PointsGot it! Thank you sir!
all_movies = session.query(Movie).order_by(Movie.movie_title).all()