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JavaScript JavaScript Loops, Arrays and Objects Tracking Multiple Items with Arrays Removing Items from an Array

Posted by anitap
anitap
5,372 Points

I pasted this in the Chrome console and it worked. I don't understand why the program says the value is not stored.

var orderQueue = ['1XT567437','1U7857317','1I9222528']; var shipping = []; shipping.push('1XT567437'); orderQueue.shift('1XT567437'); "1XT567437"

shipping; ["1XT567437"] orderQueue; ["1U7857317", "1I9222528"]

script.js 
var orderQueue = ['1XT567437','1U7857317','1I9222528'];
var shipping = [];
shipping.push('1XT567437');
orderQueue.shift('1XT567437');
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Marcus Parsons
Marcus Parsons
15,719 Points

Hi Anita,

The reason you're seeing an error is that you're using static values to push and shift between arrays. The simplest method (which is also the most dynamic) is to simply set the shipping variable equal to the result of calling the shift method on orderQueue. The reason for this is that calling shift on an array returns an array that has had the first item removed and so shipping will be the orderQueue array with the first item removed.

var orderQueue = ['1XT567437','1U7857317','1I9222528'];
var shipping = orderQueue.shift();
anitap
anitap
5,372 Points
anitap
anitap
5,372 Points

Thank you!

Marcus Parsons
Marcus Parsons
15,719 Points

You are very welcome, Anita! Happy Coding!