Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Basics (Retired) Working With Numbers Numbers and Strings

Posted by Devanshi verma
Devanshi verma
1,307 Points

I have to make a new function called totalwidth using two other variables.

the code I use is like

var width = '190px'; var numofdivs = 10; var totalwidth = parseint(width) * numofdivs;

app.js 
var width = '190px';
var numOfDivs = 10;
var totalWidth
 = parseint('width') * numofDivs;
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>

2 Answers

Jeff Lemay
Jeff Lemay
14,268 Points
Jeff Lemay
Jeff Lemay
14,268 Points

You have a few uppercase/lowercase issues here and in your parseInt function you should be targeting a width variable, not a the string 'width'.

var width = '190px';
var numOfDivs = 10;
// parseInt needed a capital I
// width needed quotes removed
// numOfDivs needed capital O
var totalWidth = parseInt(width) * numOfDivs;
Devanshi verma
Devanshi verma
1,307 Points

thanks jeff, that was quite a help.

Chad Donohue
Chad Donohue
5,657 Points
Chad Donohue
Chad Donohue
5,657 Points

It looks like your parseInt call is taking in a string rather than the variable width

var totalWidth = parseInt(width) * numOfDivs;
Devanshi verma
Devanshi verma
1,307 Points

thank you so much chad!!