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Python Python Basics (2015) Shopping List App Continue

Posted by Chunxiao Li
Chunxiao Li
1,091 Points

I have problem in solving the question following:

My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, #print out the current member. Example: ["abc", "xyz"] will just print "xyz"

breaks.py 
def loopy(items):
    for each_item in item:
        if each_item[0] == 'a'
            continue
        print(each_item)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,457 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points

So close! The for loop iterable item is missing the letter s. Should be items.

Edit: a colon is missing from the end of the if statement.

Chunxiao Li
Chunxiao Li
1,091 Points

I added the s , but it still doesn't work.

Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points

Also, a colon is missing from the end of the for statement. I've updated my answer above.

Chunxiao Li
Chunxiao Li
1,091 Points

I think you mean the if statement, right? I added the colon. It works. Thank you!