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Start your free trialFarah Zahi
12,011 PointsI have done the extra challenge but I have a bug, I can't see why I have to type twice 'quit' to leave the program.
var message = [];
var student;
var searchBox;
function print(message){
var outputDiv= document.getElementById('output');
outputDiv.innerHTML =message;
}
function getStudentReport(student){
var report= '<h2> Student: ' + student.name + '</h2>';
report += '<p> Track: ' + student.track + '</p>';
report += '<p> Achievement: ' + student.achievement + '</p>';
report += '<p> Points: ' + student.points + '</p>';
return report;
}
while(true){
searchBox = prompt('Search for student or type quit to leave the prompt');
if( searchBox.toLowerCase() === 'quit'){
break
}
for(var i =0; i< students.length; i++){
student = students[i];
if(student.name === searchBox){
message.push(getStudentReport(student));
}
if (student.name !== searchBox){
searchBox = prompt( searchBox +" is not a student, try again. Search for student or type quit to leave the prompt");
break
}else{
print(message);
}
}
}
1 Answer
Steven Parker
231,275 PointsThere are two different prompts in this code, and only one of them checks for "quit".
The response to the prompt that contains "is not a student" is ignored, and the other prompt will always be issued following it.
You might want to replace the second one with an "alert".
That might solve the immediate question, but you'll probably want to take a closer look at the overall logic. There are a number of other issues that will impede proper search operations.
Uche Onuekwusi
18,070 PointsUche Onuekwusi
18,070 PointsPlease why did you have to break at the last if statement. I thought you can only break out of loops not conditional statements
Steven Parker
231,275 PointsSteven Parker
231,275 PointsYou're right, the "break" ends the loop — the one that surrounds the conditional statement.