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Start your free trialMarleen Berg
22,524 PointsI have a different solution, is this correct?
var minNumber = prompt("give your min number!");
var maxNumber = prompt("give your max number");
var diceRoll = Math.floor(Math.random() * parseInt(maxNumber) + parseInt(minNumber))+1;
alert(diceRoll);
I will have correct results, as far as I did test....
2 Answers
Alexander Davison
65,469 PointsI found a bug. I set minNumber
to 5, and maxNumber
to 11, and I got 15.
Hint on fixing bug: Sometimes, Math.random() * maxNumber
can be close to maxNumber
, because Math.random()
can be close to 1, and if you add minNumber
to that quantity, it may be above maxNumber
.
Steven Parker
231,268 PointsThe math being applied here is not correct for creating a random number that will be within the two limits entered. The formula shown here will give you a number with a minimum one higher than the lower value, and a maximum of the sum of the two numbers entered.
The correct formula for a within-range random number with even distribution is:
random * range + minimum
where "range" is maximum - minimum + 1
Adomas Domeika
6,151 PointsAdomas Domeika
6,151 Pointsyep, looks like your code is correct.
Sorry. Changing my opinion, why? Because if you enter your max number 20 an min number 15, then if random generates 18, you add the min number and the answer is 33. Sorry for the wrong answer.