Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialChristopher Nelson
5,844 PointsI dont understand why it does not pass
I solved this problem two different ways that I believe are valid, but the system says that they are both incorrect. The for loop prints exactly the output onto the screen and fails.
<?php
//edit this array
$contacts = array(
array(
"name" => "Alena Holligan",
"email" => "alena.holligan@teamtreehouse.com"
),
array(
"name" => "Dave McFarland",
"email" => "dave.mcfarland@teamtreehouse.com"
),
array(
"name" => "Treasure Porth",
"email" => "treasure.porth@teamtreehouse.com"
),
array(
"name" => "Andrew Chalkley",
"email" => "andrew.chalkley@teamtreehouse.com"
)
);
// THE INSTRUCTIONS ASK FOR YOU TO REPLACE THE HARD CODED VALUES WITH THE ARRAY VALUES.
//I DID THIS WITH A FOREACH LOOP AND IT PRINTS TO THE SCREEN CORRECTLY BUT I GET AN ERROR ANYWAY
echo "<ul>\n";
foreach($contacts as $item){
echo "<li>" . $item['name'] . " : " . $item['email'] . "</li>";
};
echo "</ul>\n";
//SO THEN I TRIED TO JUST REPLACE THE HARD CODED NAMES AND EMAILS WITHOUT USING A LOOP, BUT THAT DOES NOT WORK EITHER.
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>"$contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>";
echo "<li>"$contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>";
echo "<li>"$contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>";
echo "<li>"$contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>";
echo "</ul>\n";
1 Answer
Steven Parker
231,275 PointsClose! But each line is missing a concatenation operator and a newline symbol:
<?php
//...
echo "<li>"$contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>"; // original
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n"; // fixed