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Java Java Objects Creating the MVP Counting Scrabble Tiles

Brad Palmer
Brad Palmer
2,460 Points

I don't understand this question at all! Please help!

Now in your new method, have it return a number representing the count of tiles that match the letter that was passed in to the method. Make sure to check Example.java for some example uses.

ScrabblePlayer.java
public class ScrabblePlayer {
  // A String representing all of the tiles that this player has
  private String tiles;

  public ScrabblePlayer() {
    tiles = "";
  }

  public String getTiles() {
    return tiles;
  }

  public void addTile(char tile) {
    tiles += tile;
  }

  public boolean hasTile(char tile) {
    return tiles.indexOf(tile) != -1;
  }
  public int getCountOfLetter(char letter);
    }
  }

  }
}
Example.java
// This code is here for example purposes only
public class Example {

  public static void main(String[] args) {
    ScrabblePlayer player1 = new ScrabblePlayer();
    player1.addTile('d');
    player1.addTile('d');
    player1.addTile('p');
    player1.addTile('e');
    player1.addTile('l');
    player1.addTile('u');

    ScrabblePlayer player2 = new ScrabblePlayer();
    player2.addTile('z');
    player2.addTile('z');
    player2.addTile('y');
    player2.addTile('f');
    player2.addTile('u');
    player2.addTile('z');

    int count = 0;
    // This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
    count = player1.getCountOfLetter('p');
    // This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
    count = player1.getCountOfLetter('d');
    // This would set 0, because there isn't an 'a' tile in player1's tiles
    count = player1.getCountOfLetter('a');

    // This will return 3 because player2 has 3 'z' tiles in his collection of tiles
    count = player2.getCountOfLetter('z');
    // This will return 1 because player2 has 1 'f' tiles in his collection of tiles
    count = player2.getCountOfLetter('f');
  }
}

2 Answers

Linda de Haan
Linda de Haan
12,413 Points

You have to finish the getCountOfLetter() method in the challenge. This is one way to do that:

    public int getCountOfLetter(char letter) {
        int count = 0;

        char[] charArray = tiles.toCharArray();
        for (char c : charArray) {
            if (c == letter) {
                count++;
            }
        }
        return count;
    }

So every time the letter argument passed in matches one of the chars in the charArray it counts 1 to the int count and at the end it returns count, so you'll have the total amount of occurrences of the letter.

Kevin Verbeek
Kevin Verbeek
5,499 Points

The question requires an enhanced for loop. I tried your solution but it doesn't work...

Linda de Haan
Linda de Haan
12,413 Points

It does work, but the question requires you to write it down differently. The for loop I used is enhanced. Do it like this and you pass:

public int getCountOfLetter(char letter) {
    int count = 0;

    // char[] charArray = tiles.toCharArray();
    for (char c : tiles.toCharArray()) {
      if (c == letter) {
        count++;
      }
    }
    return count;
  }
Kevin Verbeek
Kevin Verbeek
5,499 Points

Linda de Haan that's what I meant, thanks for clarifying it!

I used the enhanced for loop as well and that did the trick for me!