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Java Java Basics Perfecting the Prototype String Equality

Ben Taylor
Ben Taylor
354 Points
Posted by Ben Taylor
Ben Taylor
354 Points

i dont understand how to fix this if (firstExample == thirdExample.equalsIgnoreCase()) { printf("first and ....}

i dont understand how to fox this to check whether the first ad third statement are the same regardless of case

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample == secondExample) {
  console.printf("first is equal to second");
}
if (firstExample == thirdExample.equalsIgnoreCase()) {
  printf("first and third are the same ignoring case");
}

1 Answer

Andrei Fecioru
Andrei Fecioru
15,059 Points

Hi,

I would do something like this:

if (secondExample.equals(firstExample)) {
  console.printf("first is equal to second");
}
if (thirdExample.equalsIgnoreCase(firstExample)) {
  console.printf("first and third are the same ignoring case");
}

When you do string equality tests between two strings (let's say str1 and str2) you don't do str1 == str2; you should call the equals() method on one of the strings and pass the other string as input argument, like str1.equals(str2).

Hope this helps.

Ben Taylor
Ben Taylor
354 Points
Ben Taylor
Ben Taylor
354 Points

thankyou, this was very helpful

Travis Christian
Travis Christian
19,878 Points

Andrei's solution is almost perfect, but you must include the "console" before "printf", like so:

if (secondExample.equals(firstExample)) { console.printf("first is equal to second"); } if (thirdExample.equalsIgnoreCase(firstExample)) { console.printf("first and third are the same ignoring case"); }

Andrei Fecioru
Andrei Fecioru
15,059 Points

Thanks for spotting that. Fixed it.