Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Lu Favela
Front End Web Development Techdegree Student 15,570 PointsI dont think im understanding this quite yet. can i get some help on this example?
I'm confused as to how to get the condition to work collection those three values. Can someone help break it down and explain it?
const laws = document.getElementsByTagName('li');
const indexText = document.getElementById('boldIndex');
const button = document.getElementById('embolden');
button.addEventListener('click', (e) => {
const index = parseInt(indexText.value, 10);
for (let i = 0; i < laws.length; i += 1) {
let law = laws[i];
// replace 'false' with a correct test condition on the line below
if () {
law.style.fontWeight = 'bold';
} else {
law.style.fontWeight = 'normal';
}
}
});
<!DOCTYPE html>
<html>
<head>
<title>Newton's Laws</title>
</head>
<body>
<h1>Newton's Laws of Motion</h1>
<ul>
<li>An object in motion tends to stay in motion, unless acted on by an outside force.</li>
<li>Acceleration is dependent on the forces acting upon an object and the mass of the object.</li>
<li>For every action, there is an equal and opposite reaction.</li>
</ul>
<input type="text" id="boldIndex">
<button id="embolden">Embolden</button>
<script src="app.js"></script>
</body>
</html>
1 Answer
Blake Larson
13,014 PointsYou want to check if index === i. If you enter a 1 and click the button. It will keep laws[0] normal, make laws[1] bold and laws[2] will be normal.