i cant write correctly the parseInt value and am not sure where exactly to put it in the code

Question

afdsf

script.js

var a = 10;
var b = 20;
var c = 30;
if ( parseInt(a) >== parseInt(b)) {
  alert( a " is greater than " b);
    } else {
      alert(a ' is not greater than ');
    }

index.html

<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

Answer 1 · 2017-09-05T14:39:59Z

September 5, 2017 2:39pm

Hi there,

You're really close here, and you have the right idea - you don't need to parseInt() at all. When the variables are declared at the top, they do not have quotes around them, which means they are already being stored as integers - no parsing needed! A string variable can be identified by either single (') or double(") quotes. Also, be careful when the instructions ask you to compare values - I noticed you use the greater than or equal to operator, but the challenge instructions just ask for greater than. When I tried with >=, it failed, so I think it does check for that. So, you can just do something like this:

if ( a > b ) {
  alert("a is greater than b");
} else {
  alert("a is not greater than b");
}

Does that make sense? Let me know if you still have trouble.

Happy coding!

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Petya Katsarova

Petya Katsarova

i cant write correctly the parseInt value and am not sure where exactly to put it in the code

1 Answer

Katie Wood

Katie Wood