Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Lucas Huerta-Murillo Grau
PLUS
Lucas Huerta-Murillo Grau
Courses Plus Student 1,365 Points
Posted by Lucas Huerta-Murillo Grau
Lucas Huerta-Murillo Grau
Courses Plus Student 1,365 Points

I can't find the bug.

I can't see what I am doing wrong.

index.html 
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js 
let listItems = document.querySelectorAll('#rainbow');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}
Reid Everett
Reid Everett
14,009 Points
Reid Everett
Reid Everett
14,009 Points

You need to select all of the "list items" from the ID of the element you're selecting. Line 1 is missing something and get rid of the space from "i ++"

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

Actually, while it may look odd, the space before the post-increment operator doesn't cause a problem, and changing it is not part of this challenge.

1 Answer

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

You would not normally use querySelectorAll with a single ID.

Since an ID must be unique, you would most likely want to get a single element instead of a collection.

But in this case you really do want a collection, and specifically list items ("li"). So you might want to use a descendant selector combining that type with your list ID. Or you could get the list as a single element (with a different method) and then take the children property of that.