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MUZ141140 Dennis Pomerai
10,215 PointsI am stuck here can someone kindly help me
time_machine did not return right date
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(integer, string):
if string == 'hours' :
return starter + datetime.timedelta(hours = integer)
elif string == 'days' :
return starter + datetime.timedelta(days = integer)
elif string == 'year' :
return starter + datetime.timedelta(year = integer*365 * 9)
elif string == 'minutes' :
return starter + datetime.timedelta(minutes = integer)
time_machine(3,'days')
1 Answer
Gunhoo Yoon
5,027 PointsThe year part is messing you up.
# Remember, you can't set "years" on a timedelta!
The expected argument for year is 'years' not 'year'
elif string == 'years' :
The unit conversion and keyword argument is wrong.
x * 365 * 9 does not land you anywhere near year.
timedelta does not support years so you need to convert it. In this case, shortest one is days = integer * 365
return starter + datetime.timedelta(days = integer * 365)
Solved.