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Start your free trialGeet Aneja
2,091 PointsI added 5 to $integerOne. It is still not passing.
Help?
<?php
//Place your code below this comment
$integerOne = 1 + 5;
$integerTwo = 2 - 1;
?>
1 Answer
Danilo Mezgec
23,860 PointsYou need to sum and subtract the values to the variable.
For i.e.:
<?php
$foo = 100;
$foo = $foo + 1;
In this way you declare the varible first, and then you reuse it later on and update it.
What's the sense?
Let's say that you have a for cycle for example, that runs a certain amount of time, and you want to update the value of $foo each time that a particular condition appends, you can have something like that (pseudocode):
<?php
$foo = 5; //for some reason we need to start from 5, doesn't matter why
for([FOR CONDITION HERE]){
if([SOMETHING IS TRUE]){
//Some other useful code
$foo++; //This will add 1 to $foo, same as $foo = $foo + 1;
}
}
echo $foo; //We will see how many times the conditional statement has been true. For i.e. if the result is 8, it means that it was true 3 times
charquise
1,274 Pointscharquise
1,274 PointsHi Geet,
For task 2 your code should be