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Android Build a Simple Android App (2014) Basic Android Programming Using the Random Class

Posted by Henry Gines
Henry Gines
1,365 Points

How to declare a String variable IntAsString?

Declare a String variable named intAsString. Convert the randomNumber integer to a String value and store it in the intAsString variable. Hint: "Moosh" them together like in the video!

This is what I did. Random randomGenerator= new Random(); int randomNumber=randomGenerator.nextInt(10); String fact=""; fact=randomNumber + "";

And this what it says: Bummer! There is a compiler error. Please click on preview to view your syntax errors! Editor Recheck work. Output.html JavaTester.java:60: cannot find symbol symbol : variable intAsString location: class JavaTester if (!(intAsString instanceof String)) { ^ JavaTester.java:64: cannot find symbol symbol : variable intAsString location: class JavaTester if (!intAsString.equals(Integer.toString(randomNumber))) { ^ 2 errors

Any suggestions please...

5 Answers

Matin Shoghi
Matin Shoghi
10,978 Points
Matin Shoghi
Matin Shoghi
10,978 Points

Your last part is the problem. The code should look like this:

    Random randomGenerator = new Random();
    int randomNumber = randomGenerator.nextInt(10);
    String intAsString = randomNumber + "";
Henry Gines
Henry Gines
1,365 Points

Thank you very much Matin.

Gloria Dwomoh
Gloria Dwomoh
13,116 Points
Gloria Dwomoh
Gloria Dwomoh
13,116 Points

The challenge says declare a String variable named intAsString, but you have named yours as "fact" instead :)

Henry Gines
Henry Gines
1,365 Points
Henry Gines
Henry Gines
1,365 Points

Hi Gloria,

Thank you for your response. But unfortunately, still I can't pass the challenge.

This is what I wrote: Random randomGenerator=new Random(); int randomNumber = randomGenerator.nextInt(10); String=intAsString. Random randomNumber= new String(); And this is what I got: Bummer! There is a compiler error. Please click on preview to view your syntax errors! JavaTester.java:22: ';' expected Random randomNumber= new String(); ^ 1 error

Gloria Dwomoh
Gloria Dwomoh
13,116 Points

It's because you changed the wrong thing :) I said you should change "fact" to intAsString. You should swap fact with intAsString. You can make it all a single line declaration as Matin showed below.

Henry Gines
Henry Gines
1,365 Points
Henry Gines
Henry Gines
1,365 Points

Thanks Gloria and Matin.

Gloria Dwomoh
Gloria Dwomoh
13,116 Points

You are welcome Beau.

J Meacham
J Meacham
932 Points
J Meacham
J Meacham
932 Points

Thank you! This one was a stumper for me until I saw your response Matin Shoghi!