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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Mykiel Horn
Mykiel Horn
4,014 Points

How come my function isn't outputting the right number of prints?

I placed all of my code into workspaces and when I run my code it does what I think is correct. It prints 5 random numbers and tells me are they even or odd. But when I run my code in the Code Challenge, it says that my code has the wrong number of prints. Can anyone tell me what am I missing so I can complete this code challenge?

even.py 
import random

start = 5

def even_odd(start):
    while start > 0:
        rannum = random.randint(1,99)
        if rannum%2 == 0:
            print("{} is even".format(rannum))
        else:
            print("{} is odd".format(rannum))
        start = start - 1
    return
Rob Enderle
Rob Enderle
2,164 Points
Rob Enderle
Rob Enderle
2,164 Points

I believe they wanted you to create the while loop outside and not modify the function, although your code does produce the intended result when called.

You'd need to put

even_odd(start)

outside, after your function.

If you wanted to use the function as provided, you could do something like the following:

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start:
    rannum = random.randint(1, 99)

    if even_odd(rannum):
        print('{} is even'.format(rannum))
    else:
        print('{} is odd'.format(rannum))
    start -= 1

2 Answers

Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,722 Points
Jeff Muday
Jeff Muday
Treehouse Moderator 28,722 Points

You got most of the code correct. But your interpretation of the challenge needs to be modified.

They are asking you to treat even_odd() as a stand-alone function and build your code to utilize the function is a checker for even and odd numbers.

import random

# leave even_odd just like they gave it to you.
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

# your challenge code goes here.
start = 5
while start:
    rannum = random.randint(1,99)
    if even_odd(rannum):
        print("{} is even".format(rannum))
    else:
        print("{} is odd".format(rannum))
    start = start - 1
Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,722 Points
Jeff Muday
Jeff Muday
Treehouse Moderator 28,722 Points

Yes, you can do it the alternate way of modifying even_odd, it will also pass the challenge. So, as with any challenge, there are all different ways to write them. In this case, Mykeil's modification of even_odd will pass muster.

see below:

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    while num:
        rannum = random.randint(1,99)
        if rannum % 2:
            print("{} is odd".format(rannum))
        else:
            print("{} is even".format(rannum))
        num -= 1

start=5
even_odd(start)