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JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Ali Sh
Ali Sh
2,026 Points
Posted by Ali Sh
Ali Sh
2,026 Points

How can i solve this?

We have some JavaScript code that will cycle over list items and apply colors from an array called colors. The code will apply the first color to the first list item, the second color to the second list item and so on. But the code is not complete. On line 1 of app.js, set the variable listItems to refer to a collection. The collection should contain all list items in the unordered list element with the id of rainbow.

index.html 
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js 
let listItems = document.getElementsByTagName('rainbow');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}

1 Answer

tobiastrinkler
seal-mask
.a{fill-rule:evenodd;}techdegree
tobiastrinkler
Full Stack JavaScript Techdegree Student 16,538 Points
tobiastrinkler
.a{fill-rule:evenodd;}techdegree
tobiastrinkler
Full Stack JavaScript Techdegree Student 16,538 Points

Hi Ali, In your case you are just grabbing all the ul's in the document. What you want to do is grab all the list items within the unordered list. I used the querySelectorAll to grab onto all li items in the list. I first select the ul with the id of rainbow and the all list items :).

let listItems = document.querySelectorAll('#rainbow li');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}```