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Start your free trialMarkus Garmeister
1,465 PointsHow can I filter list elements by there first letter?
continents = [ 'Asia', 'South America', 'North America', 'Africa', 'Europe', 'Antarctica', 'Australia', ] n=0 while n <= len(continents) - 1: a_continent = continents[n] if a_continent[0] == "A": a_continents = a_continents.append(a_continent) else: print(a_continents)
continents = [
'Asia',
'South America',
'North America',
'Africa',
'Europe',
'Antarctica',
'Australia',
]
n=0
while n <= len(continents) - 1:
a_continent = continents[n]
if a_continent[0] == "A":
a_continents = a_continents.append(a_continent)
else:
print(a_continents)
1 Answer
Reuben Rushton-Taylor
3,374 PointsFirst of all, you will need to define a_continents as a list, as it is not defined.
Within your if statement, you only need a_continents.append, as the .append will assign the continent to the list.
You should also increment 'n' as you go, otherwise the while loop will loop forever.
Example:
continents = [
'Asia',
'South America',
'North America',
'Africa',
'Europe',
'Antarctica',
'Australia',
]
a_continents = [] #defining a_continents
n=0
print(len(continents))
while n <= (len(continents) - 1):
a_continent = continents[n]
n +=1 #incrementing n
if a_continent[0] == "A":
a_continents.append(a_continent) #appending a list
else:
print(a_continents)
alternatively swap out with a for loop:
for x in continents:
if x[0] == "A":
a_continents.append(x)
print(a_continents)
Louise St. Germain
19,424 PointsLouise St. Germain
19,424 PointsHi Reuben,
I just changed this to an answer so others can see it, and so it has a chance to get upvoted/selected as best answer!