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Python Python Basics (2015) Letter Game App Random Item

Hi, sorry i don't get this bit at all, could anyone explain?

not even sure what's really being asked!

item.py
# EXAMPLE
# random_item("Treehouse")
# The randomly selected number is 4.
# The return value would be "h"
import random
def random_item(iter(arg1)):
    ran_num = random.randint(0, len(arg1) - 1)
    return arg1[ran_num]

question is this btw: First, import the random library. Then create a function named random_item that takes a single argument, an iterable. Then use random.randint() to get a random number between 0 and the length of the iterable, minus one. Return the iterable member that's at your random number's index.

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points

You are VERY close. Remove the iter() wrapper from the parameter arg1.

import random
def random_item(arg1):  # <-- removed 'iter()' wrapper
    ran_num = random.randint(0, len(arg1) - 1)
    return arg1[ran_num]

cheers man, not a clue what the iter() wrapper actually is, just thought from the questions wording that it had to be specifically formatted as an iterable. ...Though i guess a string is an iterable as long as it's 2 or more characters long, right?

Chris Freeman
Chris Freeman
Treehouse Moderator 68,426 Points

In truth, even a one character string is iterable. A zero-length string is "False-y" so no iteration occurs.