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JavaScript

Posted by Lewis Sheeran
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Lewis Sheeran
Web Development Techdegree Graduate 19,398 Points

Here's my solution. I tried to make it as lean as possible. I'm sure there's a more concise way.. let me know!

firstNum = prompt("Enter your first number");
secondNum = prompt("Enter your second number");


if ( isNaN(firstNum) || isNaN(secondNum) ) {
  alert("Please enter numerical values only");
}
  else if ( parseInt(secondNum) === 0 ) {
  alert ("You cannot divide by zero. Reload and try again");
}
  else {
    document.write(`<h1> Math with numbers ${firstNum} and ${secondNum}</h1>`)
    document.write(`<p> ${firstNum} + ${secondNum} = ${parseInt(firstNum) + parseInt(secondNum)} </p>`);
    document.write(`<p> ${firstNum} x ${secondNum} = ${parseInt(firstNum) * parseInt(secondNum)} </p>`);
    document.write(`<p> ${firstNum} / ${secondNum} = ${parseInt(firstNum) / parseInt(secondNum)} </p>`);
    document.write(`<p> ${firstNum} - ${secondNum} = ${parseInt(firstNum) - parseInt(secondNum)} </p>`);

}

1 Answer

martinjones1
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.a{fill-rule:evenodd;}techdegree seal-36
martinjones1
Front End Web Development Techdegree Graduate 44,824 Points
martinjones1
.a{fill-rule:evenodd;}techdegree seal-36
martinjones1
Front End Web Development Techdegree Graduate 44,824 Points

Nice work!

You could use just one call to document.write like that shown below:

firstNum = prompt("Enter your first number");
secondNum = prompt("Enter your second number");

if ( isNaN(firstNum) || isNaN(secondNum) ) {
  alert("Please enter numerical values only");
}
  else if ( parseInt(secondNum) === 0 ) {
  alert ("You cannot divide by zero. Reload and try again");
}
  else {
    document.write(`
        <h1>Math with numbers ${firstNum} and ${secondNum}</h1>
        <p>${firstNum} + ${secondNum} = ${parseInt(firstNum) + parseInt(secondNum)}</p>
        <p>${firstNum} x ${secondNum} = ${parseInt(firstNum) * parseInt(secondNum)}</p>
        <p>${firstNum} / ${secondNum} = ${parseInt(firstNum) / parseInt(secondNum)}</p>
        <p>${firstNum} - ${secondNum} = ${parseInt(firstNum) - parseInt(secondNum)}</p>
    `);
}

There is a few other things you could do as well to make it leaner, but honestly, right now I would not sweat it, as you pick these things up over time, you will apply them more and more.