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Java Java Basics Perfecting the Prototype String Equality

Andrew Peterson
Andrew Peterson
1,192 Points
Posted by Andrew Peterson
Andrew Peterson
1,192 Points

Having some troubles with equalsIgnoreCase.

Not sure if I am using the IgnoreCase correctly. Any insight would be greatly appreciated!

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {console.printf("%s is equal to %s.", firstExample, secondExample);
                                   }
if (firstExample == thirdExample.equalsIgnoreCase("hello")) {
  console.printf("first and third are the same ignoring case");
}
Andrew Peterson
Andrew Peterson
1,192 Points
Andrew Peterson
Andrew Peterson
1,192 Points

Not sure if the challenge question is posted but here it is - Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "first and third are the same ignoring case".

1 Answer

jb30
jb30
44,807 Points

It is possible in Java for two Strings with the same characters to have different addresses in memory. For example,

String example1 = new String("hello");
String example2 = new String("hello");
System.out.println(example1 == example2); // Prints false

To check if firstExample and secondExample have the same characters, the first if block would become

if (firstExample.equals(secondExample)) {
    console.printf("%s is equal to %s.", firstExample, secondExample);
}

To check if firstExample and secondExample have the same characters ignoring case, the first line would become 

if (firstExample.equalsIgnoreCase(secondExample)) {