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Python Dates and Times in Python (2014) Let's Build a Timed Quiz App Harder Time Machine

Harder time_machine

Why won't either of these work. Please explain. Thank you.

time_machine.py
import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(n, string):
  if string == 'minutes': return starter + datetime.timedelta(minutes = n) 
  if string == 'hours': return starter + datetime.timedelta(minutes = n)
  if string == 'days': return starter + datetime.timedelta(minutes = n)
  if string == 'years': return starter + datetime.timedelta(days = n*365)

def time_machine(n, string):
  if string == 'years':
    n = n*365
  else:
    continue

  return starter + datetime.timedelta(string = n)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points

Your code is very close. It appears you have a copy and paste issue:

import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

def time_machine(n, string):
  if string == 'minutes': return starter + datetime.timedelta(minutes = n) 
  if string == 'hours': return starter + datetime.timedelta(minutes = n)  #  <-- changed to 'hours'
  if string == 'days': return starter + datetime.timedelta(minutes = n)  #  <-- changed to 'days'
  if string == 'years': return starter + datetime.timedelta(days = n*365)

  return starter + datetime.timedelta(string = n)