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Python Python Collections (2016, retired 2019) Lists Disemvowel

Lukas Coffey
Lukas Coffey
20,382 Points
Posted by Lukas Coffey
Lukas Coffey
20,382 Points

Function works in local environment but not in Challenge

On my local machine this returns the correct results. For instance: disemvowel("Vowel") = "Vwl"

disemvowel.py 
def disemvowel(word):
    list_word = list(word)
    vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]

    for letter in list_word:
        if letter in vowels:
            list_word.remove(letter)
    new_word = "".join(list_word)
    return new_word

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

try it with a word that has consecutive vowels. it won't work because you are modifying a list while looping through it. the remove method takes the specified element out, then all elements after that element shift left. the loop moves on though, resulting in skipped elements. to solve make a copy of the list and loop through that while modifying the original (or vice versa) and it won't skip elements any more.