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Start your free trialJoshua Hardy
17,317 PointsFunction named pagination, accepts four arguments
I keep getting an error with line 29. I've been scratching my head for awhile but can't figure it out. I tried with and without the curly brackets. Both ways give me errors.
<?php
include "pagination.php";
/* add function here */
function pagination($total_pages, $current_page, $section, $search) {
/* setting pagination variable */
$pagination = "<div class=\"pagination\">";
$pagination .= "Pages: ";
for ($i = 1;$i <= $total_pages;$i++) {
if ($i == $current_page) {
$pagination .= " <span>$i</span>";
} else {
$pagination .= " <a href='catalog.php?";
if (!empty($search)) {
$pagination .= "s=".urlencode(htmlspecialchars($search)) . '&' ;
} else if (!empty($section)) {
$pagination .= "cat=".$section . '&';
}
$pagination .= "pg=$i'>$i</a>";
}
}
$pagination .= "</div>";
return $pagination;
}
/* displaying the pagination */
echo $pagination($total_pages, $current_page, $section, $search){};
1 Answer
Joshua Hardy
17,317 PointsI figured it out. On line 29 I did not need the '$' in front of pagination.