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Start your free trialZubeyr Aciksari
21,074 PointsFinally, we need to update the length of the array returned in the Creator's 'newArray()' method. Use the size parameter
Hi, can u please help me? I am stuck in here.. Thanks!
public class VideoGame implements Parcelable {
public String mTitle = "";
public int mYear = 0;
public VideoGame() {
// intentionally blank
}
// getters and setters omitted for brevity!
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(mTitle);
dest.writeInt(mYear);
}
public VideoGame(Parcel in) {
// Task 1 code here!
mTitle = in.readString();
mYear = in.readInt();
}
public static final Creator<VideoGame> CREATOR = new Creator<VideoGame>() {
@Override
public VideoGame createFromParcel(Parcel source) {
// Task 2 code here!
VideoGame videoGame= new VideoGame(source);
return videoGame;
}
@Override
public VideoGame[] newArray(int size) {
// Task 3 code here!
VideoGame videoGame= new VideoGame[size];
return new videoGame[0];
}
};
}
2 Answers
Ken Alger
Treehouse TeacherZubeyr;
You are close, let's take a look.
Task 3
Finally, we need to update the length of the array returned in the Creator's 'newArray()' method. Use the size parameter passed in.
Here's the prompting code for that newArray()
method:
@Override
public VideoGame[] newArray(int size) {
// Task 3 code here!
return new VideoGame[0];
}
To complete the challenge we need to have newArray()
return a new VideoGame
array of size size
, right? We can do that by having it return a new VideoGame[size]
, which will allow us to call the method in our code as newArray(1500)
and we will get a brand new VideoGame
array object with a size of 1500.
If you are still stuck, please post back.
Happy coding,
Ken
Zubeyr Aciksari
21,074 PointsThanks!