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JavaScript JavaScript and the DOM (Retiring) Making Changes to the DOM DOM Manipulation

Posted by Mark Wisdom Reeves
.a{fill-rule:evenodd;}techdegree seal-36
Mark Wisdom Reeves
Full Stack JavaScript Techdegree Graduate 18,275 Points

Finally, append the newParagraph element to contentDiv.

var newParagraph;

newParagraph = document.createElement("p"); newParagraph = newParagraph.setAttribute("class", "panel");

var contentDiv = document.getElementById('content'); var contentDiv = document.createElement("div")[0]; var newContentDiv = contentDiv.appendChild(newParagraph);

console.log(newContentDiv);

<!DOCTYPE html> <html> <head> <title>DOM Manipulation</title> </head> <link rel="stylesheet" href="style.css" /> <body> <div id="content">

    </div>
    <script src="app.js"></script>
</body>

</html>

app.js 
var newParagraph;

newParagraph = document.createElement("p");
newParagraph = newParagraph.setAttribute("class", "panel");

var contentDiv = document.getElementById('content');
var contentDiv = document.createElement("div")[0];
var newContentDiv = contentDiv.appendChild(newParagraph);

console.log(newContentDiv);
index.html 
<!DOCTYPE html>
<html>
    <head>
        <title>DOM Manipulation</title>
    </head>
    <link rel="stylesheet" href="style.css" />
    <body>
        <div id="content">

        </div>
        <script src="app.js"></script>
    </body>
</html>

1 Answer

Steven Parker
Steven Parker
231,271 Points
Steven Parker
Steven Parker
231,271 Points

Here's a few hints:

  • don't change the assignment of "contentDiv" originally provided
  • when you set the attribute of "newParagraph", don't also reassign it
  • don't redeclare (or reassign) "contentDiv"
  • when you append to "contentDiv", you don't need to create or assign a new variable