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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Noel Guerra
Noel Guerra
940 Points

Even_odd : While loop

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

not sure what I'm doing wrong here please help

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2



while start:
    random_num = random.randint(1, 99)
    if even_odd(random_num) == True
        print("{} is even".format(random_num))
    else:
        print("{} is odd".format(random_num))

    start -=1

1 Answer

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

You just have one little typo — your "if" statement is missing the colon at the end. Otherwise, good job! :+1:

Optionally, you can leave off the " == True" part, since anything that returns a boolean (true/false) value can be tested by itself without a comparison.

Noel Guerra
Noel Guerra
940 Points

Thanks ! I can always count on you!