Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Posted by Edward Torres
Edward Torres
6,158 Points

Don't know how to solve this.

Can't figure out the solution.

minutes.py 
import datetime
def minutes(datetime1, datetime2)
    return round(10)((datetime2-datetime1).seconds/60)

1 Answer

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

Using:

round(10)((datetime2-datetime1).seconds/60)

Will attempt to pass the result of (datetime2-datetime1).seconds/60 as an argument to the result of round(10). Since round results in an int it can't be treated as a callable.

Besides that you do have the logic correct, so just apply the round function like this:

round( (datetime2-datetime1).total_seconds() / 60 )
Vittorio Somaschini
Vittorio Somaschini
33,371 Points
Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hi Edward Torres,

please also note that you are missing a colon in the function definition.

;)