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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by beijiayu
.a{fill-rule:evenodd;}techdegree
beijiayu
Android Development Techdegree Student 11,300 Points

Does anyone know what is wrong with this code?

Does anyone know what is wrong with this code

even.py 
import random

start = 5

def even_odd(num):
    while start:
    # If % 2 is 0, the number is even.
      x = random.randint(1, 99)
      if x % 2 == 0:
        print("{} is even".format(x))
      else:
        print("{} is odd".format(x))
      start = start - 1
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

christopherkaczenski
christopherkaczenski
16,079 Points
christopherkaczenski
christopherkaczenski
16,079 Points

The function even_odd() should be called not modified. Try placing your while loop beneath the function, and calling the function with the random number you generate as the argument.