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Python Python Collections (2016, retired 2019) Lists Disemvowel

Nikolay Komolov
Nikolay Komolov
23,033 Points

Disemvowel function seems to work but the test doesn't pass

Hello everybody. I tested this code and it seemed to work. However, the test doesn't pass. Have I done anything wrong here? Thanks!

disemvowel.py
def disemvowel(word):
    word = list(word)
    for letter in word:
        if letter.lower() in 'aeiou':
            word.remove(letter)
    return ''.join(word)

3 Answers

Abdishakur Hassan
Abdishakur Hassan
3,585 Points

This works. I havent got it through first time i was on mobile device.

def disemvowel(word):
    my_list = list(word)
    for letter in word:
        if letter in "aeiouAEIOU":
            my_list.remove(letter)
    word = "".join(my_list)
    return word
Daniel Schmidt
Daniel Schmidt
9,780 Points

Try this:

def disemvowel(word):
    vowels = ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U')
    return ''.join([letter for letter in word if letter not in vowels])

If your not familiar with this syntax check out this course Python Comprehensions

Abdishakur Hassan
Abdishakur Hassan
3,585 Points

You are very close. Almost done.

Instead of returning the joined word ''' return ''.join(word) ''' first seperate the list and the word

create new list out of the parameter word and use that to join with the word

def disemvowel(word):
    my_list = list(word)
    for letter in word:
        if letter.lower() in 'aeiou':
            my_list.remove(letter)
    word = ''.join(my_list)
Savannah Logan
Savannah Logan
974 Points

i tried exactly what you out and it is still not passing....