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Start your free trialSUDHARSAN CHAKRAVARTHI
Courses Plus Student 2,434 PointsDate and Time - time machine
In the function time_machine, like to know what needs to do with the first parameter "integer". Bevause all other parameters are string and parsed into datetime.
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(intdata, minutes, hours, days):
new_minute = datetime.datetime.strptime(minutes,'%M')
new_hour = datetime.datetime.strptime(hours,'%H')
new_day = datetime.datetime.strptime(days,'%d')
new_time = starter + datetime.timedelta(hours=new_hour.hour, minutes = new_minute.minute, days = new_day.day)
return new_time
2 Answers
AR Ehsan
7,912 Pointsimport datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
def time_machine(integer, string1):
if string1 == 'hours':
return starter + datetime.timedelta(hours=integer)
elif string1 == 'days':
return starter + datetime.timedelta(days=integer)
elif string1 == 'minutes':
return starter + datetime.timedelta(minutes=integer)
elif string1 == 'years':
return starter + datetime.timedelta(days=integer*365)
time_machine(3, 'days')
AR Ehsan
7,912 PointsIf this was helpful, fell free to mark as best answer
SUDHARSAN CHAKRAVARTHI
Courses Plus Student 2,434 PointsSUDHARSAN CHAKRAVARTHI
Courses Plus Student 2,434 PointsThank You very much. You have given complete code. i misunderstood the method arguments.
Paxton Butler
6,338 PointsPaxton Butler
6,338 Pointsdo you have to use an if/else statement for this?
I assumed (maybe wronlgy) that you could do something like:
return starter + datetime.timedelta(string1=integer)
but I couldn't get it to work and thought it might be a formatting issue?