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PHP PHP Arrays and Control Structures PHP Loops For Looping

Posted by adam miller
adam miller
9,053 Points

Create a FOR loop that displays each number from 1 to 100. Make sure that you DO NOT show 0 and you DO show 100.

this is my code :

for( $i = 1 ; $i <= 100 ; $i++){ echo[$i] . "<br /> \n" ; }

I keep receiving a BUMMER that states to make sure I end on 100.

4 Answers

Rob R
Rob R
14,637 Points
Rob R
Rob R
14,637 Points

Hi Adam,

Since $i isn't an array, you can echo out $i without the brackets:

for( $i = 1 ; $i <= 100 ; $i++){ echo $i . "<br /> \n" ; }

Hope that helps!

Flávia Souza
Flávia Souza
3,049 Points
Flávia Souza
Flávia Souza
3,049 Points

Even though they say "Make sure that you DO NOT show 0 and you DO show 100.", that´s the right answer:

for ($i = 1; $i <= 100; $i++){
    echo $i . "<br/>\n";
}
Joy Manuel
Joy Manuel
6,464 Points

This worked! And it's a simple format. Can't wait till it makes sense to me. :)

Mohammed Bashiru
PLUS
Mohammed Bashiru
Courses Plus Student 4,816 Points
Mohammed Bashiru
Mohammed Bashiru
Courses Plus Student 4,816 Points

Try this

for ($i = 1; $i < 101; ++$i ){ echo $i . "\n";

if(isset($facts[$i])){ echo $facts[$i]; } echo "<br />\n"; }

Tafadzwa Bara
Tafadzwa Bara
1,175 Points
Tafadzwa Bara
Tafadzwa Bara
1,175 Points

i keep on getting PHP Parse error: syntax error, unexpected 'for' (T_FOR), expecting ')' //add your loop below this line for ($i = 1; $i<= 100; i++){ echo $i . "<br />"; }

sefaxu Meter
sefaxu Meter
Courses Plus Student 277 Points

for ( $i = 1 ; $i <= 100 ; ++$i ){ echo $i . "<br/><\n>";