Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Introducing Lists Using Lists Mutability

Debajyoti Kar
seal-mask
.a{fill-rule:evenodd;}techdegree
Debajyoti Kar
Front End Web Development Techdegree Student 2,244 Points
Posted by Debajyoti Kar
.a{fill-rule:evenodd;}techdegree
Debajyoti Kar
Front End Web Development Techdegree Student 2,244 Points

couldn't we have just equated the two variables instead of using .copy?

I understand the purpose might have been just to share the existence of such method. But instead of using

  • items = wishes.copy() could he not have just done
  • items = wishes

is there any specific case where using .copy method might be more advantageous over simply equating the two variable? Or it doesn't matter and either would work.

Philip Schultz
Philip Schultz
11,437 Points
Philip Schultz
Philip Schultz
11,437 Points

Hey, Here is a link to a conversation I had the other day. Steven explained to me why we have to use .copy() and not the equal sign. Basically, if you use the equal sign you are just making another reference to the same list. You want to make a copy of the list to accomplish most things. Read the entire thread! https://teamtreehouse.com/community/cant-use-remove-to-remove-the-list-from-inside-of-messylist-why

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

As Philip explained, a simple assignment causes the new variable to point to the same list. So if you then add another item to "wishes", when you examine "items" it will be there also! To make them independent requires a copy.

The other question Philip linked to has a discussion about equality vs. identity that you may also find helpful.

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I don't think I realized until now that it was you asking both questions!

Philip Schultz
Philip Schultz
11,437 Points
Philip Schultz
Philip Schultz
11,437 Points

Yup it was me. You've helped me out a few times now......really appreciate your help.

Debajyoti Kar
seal-mask
.a{fill-rule:evenodd;}techdegree
Debajyoti Kar
Front End Web Development Techdegree Student 2,244 Points
Debajyoti Kar
.a{fill-rule:evenodd;}techdegree
Debajyoti Kar
Front End Web Development Techdegree Student 2,244 Points

thanks, Steven and Philip. It makes sense. Since I have learned C and C++ first, sometimes I get confused as I am learning Python. Thanks for clarifying you guys.

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I can relate. I was a C/C++ developer for many years before I learned Python. Wow, what a difference! :wink:

Philip Schultz
Philip Schultz
11,437 Points
Philip Schultz
Philip Schultz
11,437 Points

I went from C to Java and now Python.... it is a little confusing. I'm currently reading this article that goes really in depth about the topic. It points out that you can think of identities in python like you did pointers in C++. Check it out, it is a good read. https://www.blog.pythonlibrary.org/2017/02/28/python-101-equality-vs-identity/

JASON LEE
JASON LEE
17,352 Points

It seems this "point" behavior applies if the new variable is assigned to another variable that is of type list. It does not seem to apply if the variable is assigned to another variable that is of type int or string. For instance with the following declaration ... A = 5 B = A ... Any subsequent change to A won't affect the value in B, and vice-versa. Whereas with this declaration ... A = ["Alpha", "Bravo", "Charlie"] B = A ... Any subsequent change in the list (i.e. push, append, extend) by referencing either variable A or B will impact both variables. Is this correct?