could not print each of the student's name out

Question

var message = ''; var student;

function print( message ) { var outputDiv = document.getElementById("output"); outputDiv.innerHTML = message;

for (var i = 0; i < students.length; i +=1) { student = students[i]; message += "<h2>Student: " + student.name + "</h2>"; } print(message); }

Answer 1 · 2017-02-10T15:15:29Z

February 10, 2017 3:15pm

Hi Yen Ho. I hope my answer still helps despite it being 3 months ago since you asked this question.

It's just some "grammatical" code errors. Check out the comments (in green) I left on your code.

var message = ''; 
var student;

function print( message ) {
var outputDiv = document.getElementById("output");
outputDiv.innerHTML = message; //you missed out a closing curly brace here!

for (var i = 0; i < students.length; i +=1) {
student = students[i];
message += "<h2>Student: " + student.name + "</h2>";
}

print(message); }//there should be no curly brace here

You could use the chrome developers tool to "debug" your code next time. It will show you the exact line where the problem is. Good luck.

Answer 2 · 2016-11-08T21:15:06Z

November 8, 2016 9:15pm

Could you please use Markdown formatting for your code? Now it is hard to read and it seems that a bunch of code is missing. For example where is the students array? Also it is worth checking where the print function ends.

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Yen Ho

Yen Ho

could not print each of the student's name out

2 Answers

Amber Lim

Amber Lim

Tatiana Vasilevskaya

Tatiana Vasilevskaya