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Android Build a Simple Android App Basic Android Programming Using the Random Class

Abdus Samad Ahmed
Abdus Samad Ahmed
487 Points
Posted by Abdus Samad Ahmed
Abdus Samad Ahmed
487 Points

Confused on what to do next??

This is what I have currently

String [] intAsString = { "This is Hard.", "This is Confusing.", "Not sure when I will understand it fully."}; Random randomGenerator = new Random(); int randomNumber = randomGenerator.nextInt(3);

get an error saying string cannot become a string or something along the lines

RandomTest.java 
String [] intAsString = {
  "This is Hard.",
  "This is Confusing.",
  "Not sure when I will understand it fully."};
Random randomGenerator = new Random();
                int randomNumber = randomGenerator.nextInt(3);

1 Answer

jacksonpranica
jacksonpranica
17,610 Points
jacksonpranica
jacksonpranica
17,610 Points

Hey Abdus,

Not sure what you're doing in your example.

Random randomGenerator = new Random();
int randomNumber = randomGenerator.nextInt(10);

These two codes of line seem to be right...except for the fact that you used a 3 instead of a 10 when it said it wanted a random range from 0 to 9.

However this line:

String [] intAsString = {
  "This is Hard.",
  "This is Confusing.",
  "Not sure when I will understand it fully."};

Not sure why you are making an array? I'm just guessing it was for fun?

Regardless,

String intAsString = Integer.toString(randomNumber);

After doing the challenge this one got me through. In here we create the string variable, use the integer function to turn the integer into a string and then store it in the variable

Feel free to leave a comment if you don't understand.