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Start your free trialJoshua Miles
545 Pointscommunication error
I am continually getting a communication error whenever i click "check work". I would like to move on to the next section and its the only thing holding me back. help!
<?php
class Fish
{
public $common_name;
public $flavor;
public $record_weight;
function __construct($name, $flavor, $record){
// $this->common_name = $name;
//$this->flavor = $flavor;
//$this->record_weight = $record;
$bass = new Fish();
$bass->common_name = "Largemouth Bass";
$bass->flavor = "Excellent";
$bass->record_weight = "22 pounds 5 ounces";
// $bass->getInfo("Largemouth Bass","Excellent","22 pounds 5 ounces");
}
public function getInfo() {
return "A {$this->common_name} is an {$this->flavor} flavored fish. The world record weight is {$this->record_weight}.";
}
}
?>
1 Answer
Brian Jensen
Treehouse StaffWhen you instantiate a class you have to be outside of it, you were still inside of fish.
<?php
class Fish
{
public $common_name;
public $flavor;
public $record_weight;
function __construct($name, $flavor, $record){
$this->common_name = $name;
$this->flavor = $flavor;
$this->record_weight = $record;
}
public function getInfo() {
return "A {$this->common_name} is an {$this->flavor} flavored fish. The world record weight is {$this->record_weight}.";
}
}
$bass = new Fish("Largemouth Bass","Excellent","22 pounds 5 ounces");
?>