Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Functions in Swift Adding Power to Functions Function Parameters

Posted by Laurie Cai
Laurie Cai
5,391 Points

Code Challenge: Function with argument labels not executing. What am I missing?

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

functions.swift 
func getRemainder(a value: Int, b divisor: Int) -> Int {
  let aModuloB = a % b

  return aModuloB
}
Jeremy Conley
Jeremy Conley
4,791 Points

You almost got it,

func getRemainder(a value: Int, b divisor: Int) -> Int {
  let aModuloB = value % divisor

  return aModuloB
}
Jeremy Conley
Jeremy Conley
4,791 Points

Actually now that I'm reading this it may be this solution, I haven't taken the course so I was just assuming,

func getRemainder(value a: Int, divisor b: Int) -> Int {
    let aModuloB = a % b

    return aModuloB
}

Either way you are just mixing up your local and external params. Here 'value' and 'divisor' are just external names to help you understand what is going into the function, you don't actually use them in the method.

2 Answers

Jeff McDivitt
Jeff McDivitt
23,970 Points
Jeff McDivitt
Jeff McDivitt
23,970 Points

This is the cleanest way to write this function

func getRemainder(value a: Int, divisor b: Int) -> Int {
    return a % b
}

let result = getRemainder(value: 10, divisor: 3)
Elliot Rutherfoord
Elliot Rutherfoord
7,684 Points
Elliot Rutherfoord
Elliot Rutherfoord
7,684 Points

Hey man looks like you already got it though there is a cleaner way to write this :)

func getRemainder(a value: Int, b divisor: Int) -> Int { return value % divisor }