Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Jason Pallone
Jason Pallone
895 Points

code challenge broken maybe?

I literally just entered this EXACT code and it said i passed, i hit the next task button and it brought me back to step 1 then to step 2 then back here and now it says bummer wrong number of prints????

even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == 5:
    num = random.randint(1, 99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

1 Answer

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

By comparing "start" to the number 5 the loop will only run one time. But it should keep running until "start" becomes 0.

Hint any non-zero value is considered "truthy" and can be tested just by naming it.