Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Build a Simple PHP Application Listing Inventory Items More Excitement With Arrays

Posted by YIHENG CHIU
YIHENG CHIU
2,761 Points

Challenge task 6 of 7

"Inside the foreach loop, we should only display one <li> tag for each flavor. The one list item should display the value for the array element that the foreach loop is considering. Remove one of the <li> elements, and change the value that gets displayed in the other to display the flavour."

I don't really understand what does it mean.

YIHENG CHIU
YIHENG CHIU
2,761 Points

Thank you very much! Now it work!!!

1 Answer

Oisin Kilkenny
Oisin Kilkenny
14,213 Points

The question is asking you to remove one of the list items and replace what will be the output.

<?php

foreach($flavors as $flavor){

?>

<li><?php echo $flavor; ?></li>

<?php

}

?>
YIHENG CHIU
YIHENG CHIU
2,761 Points

Thank you for replying my question, however I used your code <?php foreach($flavors as $flavor){ ?> <li><?php echo $flavor; ?></li> <?php } ?> but It still does't work.

YIHENG CHIU
YIHENG CHIU
2,761 Points

This is how my code looks like right now:

<?php $flavors = array(); $flavors[] = "Chocolate"; $flavors[] = "Vanilla"; $flavors[] = "Mint"; ?>

<p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors) ?> flavors of ice cream.</p>

<ul> <?php foreach($flavors as $flavor){?> <li><?php echo $flavor; ?></li> <?php } ?>
</ul>

Oisin Kilkenny
Oisin Kilkenny
14,213 Points

Up to question six, this is exactly what I have.

<?php       

    $flavors = array("Chocolate", "Vanilla", "Damn, you stole mine.");

?>
<p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p>
<ul>
    <?php
        foreach($flavors as $flavor){
    ?>
    <li><?php echo $flavor; ?></li>
    <?php
        }
    ?>
</ul>
YIHENG CHIU
YIHENG CHIU
2,761 Points 
<?php
$flavors = array();
$flavors[] = "Chocolate";
$flavors[] = "Vanilla";
$flavors[] = "Mint";
?>

I think here is the difference

Oisin Kilkenny
Oisin Kilkenny
14,213 Points

Possibly, try using my code and see if it works.

YIHENG CHIU
YIHENG CHIU
2,761 Points

Thank you very much! Now it works!

Oisin Kilkenny
Oisin Kilkenny
14,213 Points

No problem. :)